Normal Sampling Distribution Calculator

This normal sampling distribution calculator finds the standard error and the probability for a sample mean from μ, σ and n.

Checks on your data

  • The mean of the sampling distribution equals the population mean.
  • With n of 30 or more, the central limit theorem makes x̄ roughly normal for most populations.
  • Use σ here. If you only know the sample standard deviation, use a t distribution instead.

Results

P(x̄ > 103)
0.11507
Mean of the sampling distribution (μ)
100
Standard error (σ ÷ √n)
2.5
z score
1.2
Population standard deviation σ
15
Sample size n
36
Sampling distribution of the sample mean
9095100105110sample mean
Show step-by-step solution
  1. The sampling distribution of x̄ has mean μ = 100 and standard error σ ÷ √n = 15 ÷ √36 = 2.5.
  2. Standardise: z = (x̄ − μ) ÷ SE = (103 − 100) ÷ 2.5 = 1.2.
  3. P(x̄ > 103) = 0.11507.
Mean of x̄μ
Standard errorσ / √n
z(x̄ − μ) / SE

What Is Normal Sampling Distribution?

The sampling distribution of the sample mean shows how x̄ varies from sample to sample. When the population is normal, or the sample is large enough for the central limit theorem, it is normal with mean μ and standard error σ divided by the square root of n.

Enter μ, σ and n, then choose P(x̄ below a), P(x̄ above a) or P(a below x̄ below b). The calculator standardises to a z score and reads the probability from the normal curve.

Bigger samples give a smaller standard error, so the sample mean lands closer to μ.

How to Use the Normal Sampling Distribution Calculator

  1. Enter μ, σ and n.
  2. Pick less than, greater than or between and enter the value or values.
  3. Read the standard error, the z score and the probability.

Normal Sampling Distribution Formula

Standard error

SE=σnSE=\frac{\sigma}{\sqrt n}

z score of a sample mean

z=xˉ−μσ/nz=\frac{\bar x-\mu}{\sigma/\sqrt n}

Normal Sampling Distribution Variables Explained

SymbolMeaningNotes
μPopulation mean
σPopulation standard deviation
nSample size
SEStandard error of the meanσ / √n

Normal Sampling Distribution Worked Example

With the example values loaded in the calculator above, the steps are:

  1. The sampling distribution of x̄ has mean μ = 100 and standard error σ ÷ √n = 15 ÷ √36 = 2.5.
  2. Standardise: z = (x̄ − μ) ÷ SE = (103 − 100) ÷ 2.5 = 1.2.
  3. P(x̄ > 103) = 0.11507.

Result: P(x̄ > 103) = 0.11507; Standard error (σ ÷ √n) = 2.5.

Worked example

Let μ = 100, σ = 15 and n = 36. The standard error is 15 ÷ 6 = 2.5.

For P(x̄ > 103), z = (103 − 100) ÷ 2.5 = 1.2, so the probability is 1 − 0.8849 = 0.1151.

The central limit theorem

For large samples the sample mean is close to normal even if the population is not. Heavy skew needs a larger n before this works well.

Where Normal Sampling Distribution Is Used

Statistics homework

Find probabilities for a sample mean.

Quality control

Estimate how likely a batch average is to drift past a limit.

Understanding the CLT

See how the spread of x̄ shrinks as n grows.

Common Normal Sampling Distribution Mistakes to Avoid

  • Do not confuse the standard error with the standard deviation of individual values.
  • Doubling n shrinks the standard error by a factor of √2, not 2.

Normal Sampling Distribution Terms and Definitions

Standard error
The standard deviation of a sample statistic, here of x̄.
Sampling distribution
The distribution of a statistic over all possible samples.

Normal Sampling Distribution FAQs

What is the sampling distribution of the sample mean?

The distribution of x̄ across repeated samples. It has mean μ and standard deviation σ ÷ √n.

How do you find the standard error?

Divide the population standard deviation by the square root of the sample size.

When is it normal?

When the population is normal, or when n is large enough for the central limit theorem to apply.

What if σ is unknown?

Use the sample standard deviation and a t distribution.

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Last updated 2026-11-09. See our disclaimer.